# Calculate the momentum of a 1950 kg elephant charging a hunter at a speed of 7.50 m/s.

**1**

- Calculate
the momentum of a 1950 kg elephant charging a hunter at a speed of 7.50 m/s.

kg·m/s

(b) Compare the elephant’s momentum with that of a 0.0400 kg bullet fired at a speed of 600 m/s.

(momentum of elephant / momentum of bullet)

(c) What is the momentum of the 90.0 kg hunter running at 7.00 m/s after missing the elephant?

kg·m/s

**2.**

One hazard of space travel is debris left by previous missions.
There are several thousand masses large enough to detect by radar orbiting the
earth, but there are far greater numbers of very small masses such as flakes of
paint. Calculate the force exerted by a 0.170 mg
chip of paint that strikes a space shuttle window at a relative speed of 3.00 **✕** 10^{3} m/s and sticks, given
the collision lasts 6.00 **✕** 10^{-8} s.
Such a collision chipped the window of the ill-fated Challenger in June 1983,
causing $50,000 of damage.

N

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**3.**

A 0.650 kg hammer is moving horizontally at 5.00 m/s when it strikes a nail and comes to rest after driving it 1.00 cm into a board.

- Calculate
the duration of the impact.

s

(b) What was the average force exerted on the nail?

N (downward)

**4.**

Train cars are coupled together by being bumped into one another.
Suppose two loaded train cars are moving toward one another, the first having a
mass of 150,000 kg and a velocity of 0.300 m/s,
and the second having a mass of 105,000 kg
and a velocity of -0.120 m/s. (The minus indicates direction of motion.) What
is their final velocity?

m/s

**5**

Two manned satellites approaching one another at a relative speed
of 0.550 m/s intend to dock. The first has a mass of 3.00 **✕** 10^{3} kg, and the second a
mass of 7.50 **✕**10^{3} kg.
If the two satellites collide elastically rather than dock, what is their final
relative velocity? Adopt the reference frame in which the second satellite is
initially at rest and assume that the positive direction is directed from the
second satellite towards the first satellite.

m/s

**6**

A 0.0220 kg bullet moving horizontally at 450 m/s embeds itself into an initially stationary 0.500 kg block.

- What is
their velocity just after the collision?

m/s

(b) The bullet-embedded block slides 8.0 m on a horizontal surface with a 0.30 kinetic coefficient of friction. Now what is its velocity?

m/s

(c) The bullet-embedded block now strikes and sticks to a stationary 2.00 kg block. How far does this combination travel before stopping?

m

**7**

Two manned satellites approaching one another at a relative speed
of 0.300 m/s intend to dock. The first has a mass of 4.50 **✕** 10^{3} kg, and the second a
mass of 7.50 **✕**10^{3} kg.
Assume that the positive direction is directed from the second satellite
towards the first satellite.

- Calculate
the final velocity after docking, in the frame of reference in which the first
satellite was originally at rest.

m/s

(b) What is the loss of kinetic energy in this inelastic collision?

J

(c) Repeat both parts, in the frame of reference in which the second satellite was originally at rest.

final velocity

m/s

loss of kinetic energy

J

Explain why the change in velocity is different in the two frames, whereas the change in kinetic energy is the same in both. (Do this on paper. Your instructor may ask you to turn in this work.)

**8**

Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1300 kg and was approaching at 6.00 m/s due south. The second car has a mass of 850 kg and was approaching at 22.0 m/s due west.

(a) Calculate the final velocity of the cars. (Note that since
both cars have an initial velocity, you cannot use Equations 7.6a and b. You
must look for other simplifying aspects.)

Magnitude

m/s

Direction

°
(counterclockwise from west is positive)

(b) How much kinetic energy is lost in the collision? (This energy goes into
deformation of the cars.)

J